document.write( "Question 202005: the sum of two numbers is 16 when the small number is subtracted from two times the larger number the difference is 20 what are the two numbers \n" ); document.write( "
Algebra.Com's Answer #152265 by jim_thompson5910(35256)\"\" \"About 
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\"the sum of two numbers is 16\" translates to \"x%2By=16\"\r
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\n" ); document.write( "\n" ); document.write( "\"the small number is subtracted from two times the larger number the difference is 20\" translates to \"2x-y=20\"\r
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\n" ); document.write( "\n" ); document.write( "Start with the given system of equations:\r
\n" ); document.write( "\n" ); document.write( "\"system%28x%2By=16%2C2x-y=20%29\"\r
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\n" ); document.write( "\n" ); document.write( "Add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2By%29%2B%282x-1y%29=%2816%29%2B%2820%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%281x%2B2x%29%2B%281y%2B-1y%29=16%2B20\" Group like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"3x%2B0y=36\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"3x=36\" Simplify.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2836%29%2F%283%29\" Divide both sides by \"3\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=12\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2By=16\" Now go back to the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"12%2By=16\" Plug in \"x=12\".\r
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\n" ); document.write( "\n" ); document.write( "\"12%2By=16\" Multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"y=16-12\" Subtract \"12\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"y=4\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=12\" and \"y=4\".\r
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\n" ); document.write( "\n" ); document.write( "This means that the larger number is 12 and the smaller number is 4.
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