document.write( "Question 27920: Please help. Sharon invested money in a savings account at a rate of 6% simple interest. After one year she has $6996 in the account. How much did Sharon originally invest?\r
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Algebra.Com's Answer #15222 by Earlsdon(6294) $\"\"$ $\"About$

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Let x = the amount originally invested. After one year, Sharon will have $x (the original amount) plus 6% of $x (the interest earned on the original amount in one year) and this will equal $6996.00: Change the 6% to its decimal eqivalent.(6% = 0.06) and write the equation.
\n" ); document.write( " $\"x+%2B+0.06x+=+6996\"$ Combine the x-terms.
\n" ); document.write( " $\"1.06x+=+6996\"$ Divide both sides of the equation by 1.06
\n" ); document.write( " $\"x+=+6600\"$ \r
\n" ); document.write( "\n" ); document.write( "Sharon originally invested $6600.00 \n" ); document.write( "

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