document.write( "Question 201890: A mixture contains alcohol and water in the ratio 4:3. If 7 litres of water is added to the mixture, the ratio of alcohol and water becomes 3:4. Find the quantity of alcohol in the mixture ? \n" ); document.write( "
Algebra.Com's Answer #152192 by josmiceli(19441)\"\" \"About 
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Let \"a\" = liters of alcohol in original mixture
\n" ); document.write( "Let \"w\" = liters of water in original mixture
\n" ); document.write( "given:
\n" ); document.write( "(alcohol in original mixture)/(water in original mixture) = 4/3
\n" ); document.write( "\"a%2Fw+=+4%2F3\"
\n" ); document.write( "Multiply both sides by \"3w\"
\n" ); document.write( "\"3a+=+4w\"
\n" ); document.write( "\"w+=+%283%2F4%29%2Aa\" liters
\n" ); document.write( "\"a+%2F+%28%283%2F4%29%2Aa+%2B+7%29+=+3%2F4\"
\n" ); document.write( "Multiply both sides by \"%283%2F4%29%2Aa+%2B+7\"
\n" ); document.write( "\"a+=+%283%2F4%29%2A%28%283%2F4%29%2Aa+%2B+7%29\"
\n" ); document.write( "\"a+=+%289%2F16%29%2Aa+%2B+21%2F4\"
\n" ); document.write( "\"16a+=+9a+%2B+84\"
\n" ); document.write( "\"7a+=+84\"
\n" ); document.write( "\"a+=+12\"
\n" ); document.write( "There are 12 liters of alcohol in the mixture
\n" ); document.write( "check:
\n" ); document.write( "\"a+%2F+%28%283%2F4%29%2Aa+%2B+7%29+=+3%2F4\"
\n" ); document.write( "\"12+%2F+%28%283%2F4%29%2A12+%2B+7%29+=+3%2F4\"
\n" ); document.write( "\"12+%2F+%289+%2B+7%29+=+3%2F4\"
\n" ); document.write( "\"12%2F16+=+3%2F4\"
\n" ); document.write( "\"3%2F4+=+3%2F4\"
\n" ); document.write( "OK\r
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