document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=201899>Question 201899</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The St. Mark’s Community Barbecue served 250 dinners. A child’s plate cost $3.50 and an adult’s plate cost $7.00. A total of $1347.50 was collected. How many of each type of plate was served?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #152180 by </B><A HREF=/tutors/aboutme.mpl?userid=PRMath><B>PRMath(133)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=PRMath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=152180\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's just get this to the facts:\r<BR>\n" );
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document.write( "A child's plate:   3.50  (Let's refer to this as \"C\" for child)<BR>\n" );
document.write( "Adult's plate:  7.00  (Let's refer to this as \"A\" for adult)<BR>\n" );
document.write( "Total dinners served:  250<BR>\n" );
document.write( "Total amount collected:  1,347.50\r<BR>\n" );
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document.write( "So, there are two equations to think about here:\r<BR>\n" );
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document.write( "C + A = 250 dinners.   (Child plates and adult plates = 250)<BR>\n" );
document.write( "3.5C + 7.0A = 1,347.5  (Child cost TIMES the number of plates and Adult cost TIMES the number of plates will total 1,347.5)\r<BR>\n" );
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document.write( "Ok, at your first equation:  C + A = 250, let's just rewrite that and solve for \"C\"\r<BR>\n" );
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document.write( "C + A = 250<BR>\n" );
document.write( "C = 250 - A   (subtract \"A\" from both sides)\r<BR>\n" );
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document.write( "Now let's look at your 2nd equation:  3.5C + 7.0A = 1,347.5\r<BR>\n" );
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document.write( "How about \"plugging\" in the value of C that we found above?  If C = 250 - A, then let's put 250 - A in place of the \"C\" that is in the above equation.\r<BR>\n" );
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document.write( "SO, we have:\r<BR>\n" );
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document.write( "3.5C + 7.0A = 1,347.5<BR>\n" );
document.write( "3.5(250 - A) + 7.0A = 1,347.5   <BR>\n" );
document.write( "875 - 3.5A + 7.0A = 1,347.5  (I just distributed 3.5 times 250 and 3.5 times -A)<BR>\n" );
document.write( "875 + 3.5A = 1,347.5  (I just combined the \"A\" terms:  -3.5A + 7.0A = +3.5A) <BR>\n" );
document.write( "3.5A = 472.5  (I subtracted 875 from both sides)<BR>\n" );
document.write( "A = 135 (I divided both sides by 3.5)\r<BR>\n" );
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document.write( "So there were 135 adult plates.  How many children plates were there?  Well there were 250 plates TOTAL, sooooo,\r<BR>\n" );
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document.write( "250 total plates MINUS 135 adult plates  = 115 Child plates.\r<BR>\n" );
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document.write( "Therefore, our final answer is 135 Adult plates and 115 child plates.\r<BR>\n" );
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document.write( "Let's check to see if we are right...........\r<BR>\n" );
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document.write( "135 Adult plates tiimes $7.0 = $945.00<BR>\n" );
document.write( "115 Child plates times $3.50 = 402.50<BR>\n" );
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document.write( "250 Total plates              $1,347.50 total amount of money raised.\r<BR>\n" );
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document.write( "We are correct. yay. :-)\r<BR>\n" );
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document.write( "Hope this helped. :-)\r<BR>\n" );
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