document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=201939>Question 201939</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi Please help me answer this hard word problem.\r<BR>\n" );
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document.write( "An Airplane whose speed in still air is 530mi/h carries enough fuel for 10 hours of flight. On a certain flight it flies against a wind of 30 mi/h. On the return flight it travels with a wind of 30 mi/h. How far can the plane fly without refueling? \r<BR>\n" );
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document.write( "Thank you Very much,<BR>\n" );
document.write( "Leo </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #152171 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=152171\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> during the flight (against the wind) the speed is 500mph (530-30)\r<BR>\n" );
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document.write( "during the return (with the wind) the speed is 560mph (530+30)\r<BR>\n" );
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document.write( "the distance (out and back) is the same for both trips\r<BR>\n" );
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document.write( "if \"t\" is the time for the flight, then \"10-t\" is the time for the return\r<BR>\n" );
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document.write( "d = r * t, so, ___ 500 * t = 560 * (10 - t)\r<BR>\n" );
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document.write( "500t = 5600 - 560t\r<BR>\n" );
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document.write( "1060t = 5600\r<BR>\n" );
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document.write( "t = 5600 / 1060 = 280 / 53\r<BR>\n" );
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document.write( "substituting ___ d = 500 * 280 / 53 = 2641.5 mi (approx) one way </SPAN>\n" );
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