document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=201900>Question 201900</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the ratio of the area of a circle to the area of square whose diagonal is equal to the diameter of the circle ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #152168 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=152168\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the ratio of the area of a circle to the area of square whose diagonal is equal to the diameter of the circle ?<BR>\n" );
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document.write( "s = the side of the square<BR>\n" );
document.write( "Area of the square = s^2<BR>\n" );
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document.write( "The diagonal = s*sqrt(2) = diameter of the circle<BR>\n" );
document.write( "Area of the circle = pi*s^2*2/4<BR>\n" );
document.write( "Area = (pi*s^2)/2<BR>\n" );
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document.write( "ratio of circle/square = pi/2<BR>\n" );
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