document.write( "Question 27828: Hyperbolas,
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document.write( "i need to write an equations for a hyperbola centered at (-4,5) and has a vertical transverse axis. the value of \"a\" is 4 and the value of \"b\" is 9.
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document.write( " help me please!!! \n" );
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Algebra.Com's Answer #15213 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! SEE FOLLOWING TO UNDERSTAND ASYMPTOTES AND THE AXES \n" ); document.write( " \n" ); document.write( "YOU WILL FIND 2 SYMMETRIC CURVES LYING HORIZONTALLY..THEY ARE A PAIR OF HYPERBOLAS .THEIR EQN.IS \n" ); document.write( "(X^2/9)-(Y^2/9)=1...THE GENERAL EQN. IS (X^2/A^2)-(Y^2/B^2)=1 \n" ); document.write( "THE OTHER PAIR OF HYPERBOLAS WHICH ARE IN A VERTICAL POSITION ARE CALLED CONJUGATE HYPERBOLAS OF THE EARLIER 2 HYPERBOLAS.THEIR EQN.IS \n" ); document.write( "(X^2/9)-(Y^2/9)= -1...THE GENERAL EQN. IS (X^2/A^2)-(Y^2/B^2)= -1 \n" ); document.write( "NOW WE DEFINE THE VARIOUS TERMS WITH RESPECT TO THE FIRST HYPERBOLAS GIVEN BY \n" ); document.write( "(X^2/9)-(Y^2/9)=1...THE GENERAL EQN. IS (X^2/A^2)-(Y^2/B^2)=1 \n" ); document.write( "DEFINITIONS....... \n" ); document.write( "HYPERBOLA IS THE LOCUS (OR PATH TRACED)BY A POINT WHICH MOVES SUCH THAT ITS DISTANCE FROM A FIXED POINT CALLED FOCUS TO ITS DISTANCE FROM A FIXED LINE CALLED DIRECTRIX IS CONSTANT (KNOWN AS ECCENTRICITY)AND IS MORE THAN 1. \n" ); document.write( "THERE ARE 2 FOCI AND 2 DIRECTIXES FOR THE HYPERBOLA GIVEN BY THE ABOVE DEFINITION AND EQN. \n" ); document.write( "X AXIS ALONG WHICH THE 2 HYPERBOLAS LIE IS CALLED TRANSVERSE AXIS.ITS EQN.IS Y=0 \n" ); document.write( "Y AXIS ALONG WHICH THE 2 CONJUGATE HYPERBOLAS ARE PRESENT IS CALLED THE CONJUGATE AXIS.ITS EQN.IS X=0 \n" ); document.write( "IF WE CALL THE 2 POINTS ON EITHER SIDE OF ORIGIN ON THE TRANSVERSE AXIS AT DISTANCE OF A FROM THE ORIGIN ARE NAMED A AND A' THEN AA'=2A IS THE LENGTH OF TRANVERSE AXIS \n" ); document.write( "IF WE CALL THE 2 POINTS ON EITHER SIDE OF ORIGIN ON THE CONJUGATE AXIS AT DISTANCE OF B FROM THE ORIGIN ARE NAMED B AND B' THEN BB'=2B IS THE LENGTH OF CONJUGATE AXIS \n" ); document.write( "ORIGIN IS THE CENTRE OF THE HYPERBOLAS \n" ); document.write( "ECCENTRICITY OF HYPERBOLA IS GIVEN BY E={(A^2+B^2)/(A^2)}^0.5 \n" ); document.write( "FOCI ARE GIVEN BY (A/E,0)AND(-A/E,0) \n" ); document.write( "EQNS.OF DIRECTRIX 1 AND 2 ARE GIVEN BY X=A/E AND X=-A/E. \n" ); document.write( "THE 2 LINES YOU FIND DIAGONALLY ALMOST RUNNING PARALLEL TO THE CURVES AT THEIR ENDS ARE CALLED ASYMPTOTES.THE CURVES APPROACH THESE LINES AS NEAR AS WE DESIRE AT AS FAR A DISTANCE AS NEEDED,BUT NEVER TOUCH THEM .THEY RUN PARALLEL AS THE CURVES AND THE LINES EXTEND TO INFINITY . \n" ); document.write( "**************************************************************************** \n" ); document.write( "GIVEN BELOW ARE SOME MORE EXAMPLES.NOW YOU TRY TO DRAW YOUR REQUIRED CURVE AND UNDERSTAND.IF STILL IN DIFFICULTY COME BACK. \n" ); document.write( "IF CENTRE IS NOT ORIGIN BUT H,K ,THEN THE EQN OF HYPERBOLA WILL BE \n" ); document.write( "((X-H)^2/A^2)-((Y-K)^2/B^2)=1\r \n" ); document.write( "\n" ); document.write( "****************************************************************************** \n" ); document.write( "Find the equations of the vertical and horizontal asymptotes for the graph of the rational function whose equation is f(x) = x/x+3. \n" ); document.write( "LET Y =X/(X+3)..D.R IS ZERO AT X=-3..SO THIS IS A CRITICAL POINT WHERE THE FUNCTION IS NOT DEFINED. \n" ); document.write( "HENCE WE SPLIT THE DOMAIN OF X \n" ); document.write( "1. FROM -INFINITY TO LESSTHAN -3 \n" ); document.write( "2. AND GREATER THAN -3 TO +INFINITY \n" ); document.write( "THE GRAPH FOR DOMAIN \n" ); document.write( "1. FROM -INFINITY TO LESSTHAN -3 IS AS FOLLOWS. \n" ); document.write( " \n" ); document.write( "ALGEBRAICALLY , WE FIND THE RANGE OF Y VARIES FROM 1 TO INFINITY. \n" ); document.write( "SO ASYMPTOTES ARE Y=1 AS X TENDS TO MINUS INFINITY \n" ); document.write( "AND Y TENDING TO INFINITY AS X APPROACHES -3 \n" ); document.write( "THE GRAPH FOR DOMAIN \n" ); document.write( "2. FROM GREATER THAN -3 TO +INFINITY IS AS FOLLOW \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ALGEBRAICALLY , WE FIND THE RANGE OF Y VARIES FROM MINUS INFINITY TO 1. \n" ); document.write( "SO ASYMPTOTES ARE Y=1 AS X TENDS TO INFINITY \n" ); document.write( "AND Y TENDING TO MINUS INFINITY AS X APPROACHES -3 \n" ); document.write( " \n" ); document.write( " |