document.write( "Question 201872: Find two negative values of \"k\" for which the given polynomial can be factored. (there may be many possible values)\r
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Algebra.Com's Answer #152118 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
In order for \"r%5E2-2r%2Bk+\" to be factored, there must be two whole numbers that multiply to \"k\" AND add to -2. \r
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\n" ); document.write( "\n" ); document.write( "So let's pick a random number. I'm going to pick 12. Now what number must I add to 12 to get -2? Well, we can set up the equation \"12%2Bq=-2\" and solve for \"q\" to get \"q=-2-12=-14\"\r
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\n" ); document.write( "\n" ); document.write( "So the numbers 12 and -14 add to -2. They multiply to \"%2812%29%28-14%29=-168\"\r
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\n" ); document.write( "\n" ); document.write( "So it turns out that the two numbers 12 and -14 both add to -2 (the middle coefficient) AND multiply to -168. So if we let \"k=-168\", then the polynomial \"r%5E2-2r-168\" can be factored and it factors to \"%28r%2B12%29%28r-14%29\"\r
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\n" ); document.write( "\n" ); document.write( "I'll let you find another value of \"k\". Simply use the logic used above to find another \"k\" value.
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