document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=201786>Question 201786</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ali deposites $1750.00 in a registered account on march 1st 1988 at 10% compounded quarterly.Subsequently the interest rate was changed to 12% compounded monthly on september 1st,1990 and to 11% compunded semi-annually on june 1st,1992.What will the value of the deposit be on december 1st,1998,if no further changes in interest rates are changed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #152107 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=152107\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A=P(1+r/n)^rn<BR>\n" );
document.write( "3-1-88 $1750 at 10% comp quarterly<BR>\n" );
document.write( "9-1-90 $2106 at 12% comp monthly<BR>\n" );
document.write( "6-1-92 $2569.72 at 11% comp semi annually<BR>\n" );
document.write( "12-1-98 total = $3738.12<BR>\n" );
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document.write( "A=1750(1+.1/4)^7.5=1750(1.025)^7.5=1750(1.2035)=2106<BR>\n" );
document.write( "A=2106(1+.12/12)^20=2106(1.01)^20=2106(1.220)=2569.72<BR>\n" );
document.write( "A=2569.72(1+.11/2)^7=2569.72(1.055)^7=2569.72(1.4547)=3738.12 </SPAN>\n" );
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