document.write( "Question 201830: The length of a rectangle is 6 feet less than twice the width. The perimeter is 66 feet. Find the length and width. \n" ); document.write( "
Algebra.Com's Answer #152072 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=2W-6 \n" ); document.write( "2L+2W=66 \n" ); document.write( "2(2W-6)+2W=66 \n" ); document.write( "4W-12+2W=66 \n" ); document.write( "6W=66+12 \n" ); document.write( "6W=78 \n" ); document.write( "W=78/6 \n" ); document.write( "W=13 ANS. FOR THE WIDTH. \n" ); document.write( "L=2*13-6 \n" ); document.write( "L=26-6 \n" ); document.write( "L=20 ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "2*20+2*13=66 \n" ); document.write( "40+26=66 \n" ); document.write( "66=66 \n" ); document.write( " |