document.write( "Question 201830: The length of a rectangle is 6 feet less than twice the width. The perimeter is 66 feet. Find the length and width. \n" ); document.write( "
Algebra.Com's Answer #152072 by checkley77(12844)\"\" \"About 
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L=2W-6
\n" ); document.write( "2L+2W=66
\n" ); document.write( "2(2W-6)+2W=66
\n" ); document.write( "4W-12+2W=66
\n" ); document.write( "6W=66+12
\n" ); document.write( "6W=78
\n" ); document.write( "W=78/6
\n" ); document.write( "W=13 ANS. FOR THE WIDTH.
\n" ); document.write( "L=2*13-6
\n" ); document.write( "L=26-6
\n" ); document.write( "L=20 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*20+2*13=66
\n" ); document.write( "40+26=66
\n" ); document.write( "66=66
\n" ); document.write( "
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