document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=201750>Question 201750</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a retectangular playground area is 308 feet. If the lenth of the playground is 34 more feet than twice the width, find the length and width of the playground. to ear extra credut, you MUST construct an algebraic equation with a variable and solve using algebra steps.\r<BR>\n" );
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document.write( "My solution<BR>\n" );
document.write( "P=308 ft L= 2(w+34)            308= 2(60)+ 2L        308=2(60)+2(94)<BR>\n" );
document.write( "equaiton: P=2W + 2L            308=120 +2L<BR>\n" );
document.write( "308=2w +2w +68                 308-120=120-120+2L<BR>\n" );
document.write( "308=4w +68                     188=2L<BR>\n" );
document.write( "308-68=4w +68 -68              188/2=2L/2<BR>\n" );
document.write( "240=4w                         94=L  <BR>\n" );
document.write( "240/4=4w/4<BR>\n" );
document.write( "60=w </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #151989 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=151989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter = 2*Length +2 * Width<BR>\n" );
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document.write( "Given,  L=  2*W +34<BR>\n" );
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document.write( "P = 2*(2W +34) +2W<BR>\n" );
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document.write( "P = 4W +68 +2W<BR>\n" );
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document.write( "Per = 308,,,,Given<BR>\n" );
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document.write( "308 = 4W +2W +68<BR>\n" );
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document.write( "240 = 6W<BR>\n" );
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document.write( "40 = W,,,,,,,,L=(2w +34)= 2*40 +34 = 114<BR>\n" );
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document.write( "check<BR>\n" );
document.write( "P = 2W + 2L = 2(40) + 2(114) = 80 + 228 = 308,,,ok<BR>\n" );
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