document.write( "Question 201720: sue is now seven times old as louise. in six years sue will be five time as old as louise. find the present age of each one. \n" ); document.write( "

Algebra.Com's Answer #151964 by Theo(13342) $\"\"$ $\"About$

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sue is now 7 times as old as louise.
\n" ); document.write( "let x = sue's age now.
\n" ); document.write( "let y = louise's age now.
\n" ); document.write( "x = 7 * y
\n" ); document.write( "in 6 years sue will be x + 6 years old.
\n" ); document.write( "in 6 years louise will be y + 6 years old.
\n" ); document.write( "in 6 years sue will be 5 times as old as louise.
\n" ); document.write( "x + 6 = 5 * (y + 6)
\n" ); document.write( "simplify to get
\n" ); document.write( "x + 6 = 5*y + 30
\n" ); document.write( "subtract 6 from both sides of the equation and subtract 5*y from both sides of the equation to get
\n" ); document.write( "x - 5*y = 30 - 6
\n" ); document.write( "which becomes
\n" ); document.write( "x - 5y = 24
\n" ); document.write( "since x = 7y (from above) we get
\n" ); document.write( "7y - 5y = 24
\n" ); document.write( "simplify to get
\n" ); document.write( "2y = 24
\n" ); document.write( "divide both sides by 2 to get
\n" ); document.write( "y = 12
\n" ); document.write( "since y is louise's age now, then louise is 12 years old now.
\n" ); document.write( "since sue is 7 times as old as louise now, then sue is 84.
\n" ); document.write( "in 6 years from now sue will be 90 and louise will be 18.
\n" ); document.write( "sue will be 5 times as old as louise.
\n" ); document.write( "everything checks out.
\n" ); document.write( "x = sue's age now = 84
\n" ); document.write( "y = louise's age now = 12.
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