document.write( "Question 201720: sue is now seven times old as louise. in six years sue will be five time as old as louise. find the present age of each one. \n" ); document.write( "
Algebra.Com's Answer #151961 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! sue is now seven times as old as louise. in six years sue will be five time as old as louise. find the present age of each one. \n" ); document.write( "----------------------------- \n" ); document.write( "NOW DATA: \n" ); document.write( "Let louise be x yrs. old \n" ); document.write( "Then sue is 7x yrs. old \n" ); document.write( "----------------------------------- \n" ); document.write( "Six years from now DATA: \n" ); document.write( "louise will be x+6 yrs. old \n" ); document.write( "sue will be 7x+6 yrs. old \n" ); document.write( "----------------------------------- \n" ); document.write( "Equation based on 6 yrs from now data: \n" ); document.write( "sue = 5(louise) \n" ); document.write( "7x+6 = 5(x+6) \n" ); document.write( "7x+6 = 5x+30 \n" ); document.write( "2x = 24 \n" ); document.write( "x = 12 (louise's age NOW) \n" ); document.write( "7x = 84(sue's age NOW) \n" ); document.write( "================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |