document.write( "Question 27874: Could you please help me with this problem\r
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document.write( "Solve for x\r
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document.write( " Ln ( 5-x)=12
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Algebra.Com's Answer #15195 by sdmmadam@yahoo.com(530)![]() ![]() ![]() You can put this solution on YOUR website! Solve for x \n" ); document.write( "Ln ( 5-x)=12 \n" ); document.write( "By definition the logarithm of a number to a given base \n" ); document.write( "is the power to which the base has to be raised to give the number \n" ); document.write( "logb(N) = p by definition is N= (b)^p \n" ); document.write( "In the problem N=(5-x), b= e, the Naperian base and p =12 \n" ); document.write( "Therefore Loge(5-x) = 12 \n" ); document.write( "(5-x)= e^12 \n" ); document.write( "5-e^12 = x \n" ); document.write( "Answer: x = ( 5-e^12 ) \n" ); document.write( "Verification: \n" ); document.write( "log(5-x) = log[5-( 5-e^12 )] \n" ); document.write( "= log[5-5+e^12] \n" ); document.write( "= log(0+e^12) \n" ); document.write( "= log(e^12) \n" ); document.write( "=12(loge) \n" ); document.write( "= 12X1 (as loge to the same base e is 1) \n" ); document.write( "=12 which is correct\r \n" ); document.write( "\n" ); document.write( "Note: If the base is the common base 10, then we have \n" ); document.write( "Loge(5-x) = 12 giving \n" ); document.write( "(5-x)= 10^12 \n" ); document.write( "5-10^12 = x \n" ); document.write( "Answer: x = ( 5-10^12 ) \n" ); document.write( "Verification: \n" ); document.write( "log(5-x) = log[5-( 5-10^12 )] \n" ); document.write( "= log[5-5+10^12] \n" ); document.write( "= log(0+10^12) \n" ); document.write( "= log(10^12) \n" ); document.write( "=12(log10) \n" ); document.write( "= 12X1 (as log10 to the same base 10 is 1) \n" ); document.write( "=12 which is correct \n" ); document.write( " |