document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=201644>Question 201644</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sarah has 27 coins,all quarters and nickles which add up to $6.55. how many quarters does she have ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #151884 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=151884\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let N = the number of nickels and Q = the number of quarters.<BR>\n" );
document.write( "1) N+Q = 27  \"Sarah has 27 coins, all quarters (Q) and nickels (N)...\"<BR>\n" );
document.write( "2) $0.05N+$0.25Q = $6.55 \"...which add up to $6.55<BR>\n" );
document.write( "Rewrite equation 1) as N = 27-Q and substitute this into equation 2), then solve for N.<BR>\n" );
document.write( "$(0.05)(27-Q)+$0.25Q = $6.55 Simplify the left side.<BR>\n" );
document.write( "$1.35-0.05Q+0.25Q = $6.66 Add/subtract the Q-terms on the left.<BR>\n" );
document.write( "$1.35+0.2Q = $6.55 Subtract $1.35 from both sides.<BR>\n" );
document.write( "0.2Q = $5.20 Divide both sides by 0.2<BR>\n" );
document.write( "Q = 26 and N = 27-Q<BR>\n" );
document.write( "N = 27-26 = 1<BR>\n" );
document.write( "Sarah has 1 nickel and 26 quarters.<BR>\n" );
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