document.write( "Question 201636: Hi, Could you help me to find a way to this problem?!Tanks=)
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document.write( "One number is 6 less than a secound number.The product of the numbers is 48 more than the square of the smaller number.Find the two numbers.\r
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document.write( "I tryed to solve with this way but i couldnt finish it:
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Algebra.Com's Answer #151879 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! (1) x =y-6,,,,,,x = smaller, y = larger \n" ); document.write( ". \n" ); document.write( "(2) xy = 48 + x^2,,,,,product means multiply \n" ); document.write( ". \n" ); document.write( "subst (1) in (2) \n" ); document.write( ". \n" ); document.write( "y(y-6) = 48 + (y-6)^2 \n" ); document.write( ". \n" ); document.write( "y^2 -6y = 48 + y^2 -12y +36 \n" ); document.write( ". \n" ); document.write( "6y = 84 \n" ); document.write( ". \n" ); document.write( "y = 14 \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "x=y-6 = 14-6 = 8 \n" ); document.write( ". \n" ); document.write( "check in (2),,14 * 8 = 48 + 64 = 112,,,,ok \n" ); document.write( " \n" ); document.write( " |