document.write( "Question 201635: Good day.Could you please hape me to solve this question.I lernt the wey of your answers but I can not receive to the same answer as the lecture note.\r
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document.write( "Dan said Jeff:\"I'm thinking of a certain fraction whose denominator is 1 less than twice its numerator.If I add 7 to both its numerator and its denominator,I obtain the number . What is the fraction of which I'm thinking?\r
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document.write( "This is my way : So:
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document.write( "This was the solver way:
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document.write( "I always use of the first way but now I'm not sure about that! \n" );
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Algebra.Com's Answer #151870 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! I'm thinking of a certain fraction whose denominator is 1 less than twice its numerator.If I add 7 to both its numerator and its denominator,I obtain the number 3/4. What is the fraction of which I'm thinking? \n" ); document.write( "-------------------- \n" ); document.write( "Original = x/(2x-1) \n" ); document.write( "Add 7 --> (x+7)/(2x+6) \n" ); document.write( "(x+7)/(2x+6) = 3/4 \n" ); document.write( "Cross multiply \n" ); document.write( "4(x+7) = 3(2x+6) \n" ); document.write( "4x+28 = 6x+18 \n" ); document.write( "2x = 10 \n" ); document.write( "x = 5 \n" ); document.write( "---------- \n" ); document.write( "Original = 5/9 \n" ); document.write( "------------- \n" ); document.write( "Adding 7's --> 12/16 = 3/4 \n" ); document.write( "------------------------- \n" ); document.write( "Note that 5/9 is the smallest positive number that satisfies the conditions. There are an infinite number of solutions, eg \n" ); document.write( "17/25, 293/393, 1193/1593, etc. \n" ); document.write( "Multiply 3/4 by any factor and subtract 7's from the result. \n" ); document.write( "Even -1/1 fits.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |