document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=201630>Question 201630</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a triagle,the second side is one-third of the first side in length.  The third side is 2 meters less than the first side.  The perimeter of the triangle is 26 meters. Form an algebraic equation to express this problem. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #151866 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=151866\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let \r<BR>\n" );
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document.write( "x = length of the first side, <BR>\n" );
document.write( "y = length of the second side, and<BR>\n" );
document.write( "z = length of the third side\r<BR>\n" );
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document.write( "Since \"the second side is one-third of the first side in length\", this means that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=%281%2F3%29x ALIGN=MIDDLE  ALT=\"y=%281%2F3%29x\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Also, because \"The third side is 2 meters less than the first side\", we know that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=z=x-2 ALIGN=MIDDLE  ALT=\"z=x-2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Recall that the perimeter \"P\" of ANY triangle with sides of \"x\", \"y\", and \"z\" is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P=x%2By%2Bz ALIGN=MIDDLE  ALT=\"P=x%2By%2Bz\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P=x%2By%2Bz ALIGN=MIDDLE  ALT=\"P=x%2By%2Bz\"   DISABLED_style= \"max-width:90%; height:auto;\" > Start with the given equation.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=26=x%2B%281%2F3%29x%2Bx-2 ALIGN=MIDDLE  ALT=\"26=x%2B%281%2F3%29x%2Bx-2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Plug in <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P=26 ALIGN=MIDDLE  ALT=\"P=26\"   DISABLED_style= \"max-width:90%; height:auto;\" > (the given perimeter), <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=%281%2F3%29x ALIGN=MIDDLE  ALT=\"y=%281%2F3%29x\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=z=x-2 ALIGN=MIDDLE  ALT=\"z=x-2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So the algebraic equation is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=26=x%2B%281%2F3%29x%2Bx-2 ALIGN=MIDDLE  ALT=\"26=x%2B%281%2F3%29x%2Bx-2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "If you wanted to find the lengths of the three sides, you would then solve for \"x\" (to eventually find \"y\" and \"z\"). Since the problem doesn't ask for it, I'll stop here. Let me know if you want to keep going. </SPAN>\n" );
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