document.write( "Question 201548: Find the x- and y-intercepts. If no x-intercepts exist, state so.\r
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document.write( "f(x) = -x^2 + 7x - 18
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document.write( " A) No x-intercepts, (0, 18)
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document.write( " B) No x-intercepts, (0, -18)
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document.write( " C) ((-x(+ or -)sqrt 121)/(2),0) , (0, -18)
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document.write( " D) ((-x(+ or -)sqrt 121)/(2),0) , (0, 18)
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Algebra.Com's Answer #151805 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! We'll start with the y-intercept since it is easier. The y-intercept occurs when x=0. (Think about it. All the points along the y-axis have an x-coordinate that is 0.) So to find the y-intercept find the point where x=0, In other words find f(0).\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So the y-intercept is (0, 18). \n" ); document.write( "Similarly to find x-intercepts we find we y=0: \n" ); document.write( " \n" ); document.write( "Since this will not factor, we will try the quadratic formula: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "From this we can see that \n" ); document.write( "a = -1 \n" ); document.write( "b = 7 \n" ); document.write( "c = -18 \n" ); document.write( "Substituting these values into the quadratic formula we get: \n" ); document.write( " \n" ); document.write( "Simplifying: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "At this point we can go no farther. When we square any Real number we either get zero or a positive number, never a negative. So it is impossible to square a Real number and get -23. In other words |