document.write( "Question 201587: Evaluate: log (subscript 8)(1/16) Thanks. \n" ); document.write( "
Algebra.Com's Answer #151796 by jim_thompson5910(35256)\"\" \"About 
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\"log%288%2C%281%2F16%29%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%28log%2810%2C%281%2F16%29%29%29%2F%28log%2810%2C%288%29%29%29\" Use the change of base formula\r
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\n" ); document.write( "\n" ); document.write( "Note: Remember the change of base formula is \"log%28b%2C%28x%29%29=log%2810%2C%28x%29%29%2Flog%2810%2C%28b%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28log%2810%2C%282%5E%28-4%29%29%29%29%2F%28log%2810%2C%288%29%29%29\" Rewrite \"1%2F16\" as \"2%5E%28-4%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28log%2810%2C%282%5E%28-4%29%29%29%29%2F%28log%2810%2C%282%5E3%29%29%29\" Rewrite \"8\" as \"2%5E3\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28-4%2Alog%2810%2C%282%29%29%29%2F%28log%2810%2C%282%5E3%29%29%29\" Pull down the first exponent using the identity \"log%28b%2C%28x%5Ey%29%29=y%2Alog%28b%2C%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28-4%2Alog%2810%2C%282%29%29%29%2F%283%2Alog%2810%2C%282%29%29%29\" Pull down the second exponent using the identity \"log%28b%2C%28x%5Ey%29%29=y%2Alog%28b%2C%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( " Highlight the common terms.\r
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\n" ); document.write( "\n" ); document.write( "\"%28-4%2Across%28log%2810%2C%282%29%29%29%29%2F%283%2Across%28log%2810%2C%282%29%29%29%29\" Cancel out the common terms.\r
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\n" ); document.write( "\n" ); document.write( "\"-4%2F3\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "So \"log%288%2C%281%2F16%29%29=-4%2F3\"
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