document.write( "Question 201477: A cellular phone company offers a contract for which the cost C, in dollars, of t minutes of telephoning is given by C=0.25(t-65.95), where it is assumed that t>=300 minutes. What times will keep cost between $108.95 and $131.45?\r
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Algebra.Com's Answer #151744 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
take your original equation of \r
\n" ); document.write( "\n" ); document.write( "c = .25 * (t - 65.95) and solve for t.\r
\n" ); document.write( "\n" ); document.write( "divide both sides by .25 to get\r
\n" ); document.write( "\n" ); document.write( "c/.25 = t - 65.95\r
\n" ); document.write( "\n" ); document.write( "add 65.95 to both sides of the equation to get\r
\n" ); document.write( "\n" ); document.write( "(c/.25) + 65.95 = t\r
\n" ); document.write( "\n" ); document.write( "just plug in the values for the low c and the high c and you get the time in minutes that would be minimum and maximum.\r
\n" ); document.write( "\n" ); document.write( "for the minimum, the equation becomes:\r
\n" ); document.write( "\n" ); document.write( "(108.95 / .25) + 65.95 = t\r
\n" ); document.write( "\n" ); document.write( "use parentheses to make sure the order of the arithmetic is clear.\r
\n" ); document.write( "\n" ); document.write( "simplify to get\r
\n" ); document.write( "\n" ); document.write( "435.8 + 65.95 = 5\r
\n" ); document.write( "\n" ); document.write( "simplify further to get\r
\n" ); document.write( "\n" ); document.write( "t = 501.75\r
\n" ); document.write( "\n" ); document.write( "that's your low number of minutes\r
\n" ); document.write( "\n" ); document.write( "solve the equation again using c = 131.45 to get the high end minutes.\r
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