document.write( "Question 201492This question is from textbook precalculus
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document.write( ": the square root of x minus 3 square root of x with an index of 4 minus 4 equals 0 \n" );
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Algebra.Com's Answer #151702 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! The easiest way to do this is based on understanding that \n" ); document.write( "If we let \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "This equation can be easily solved by factoring: \n" ); document.write( " \n" ); document.write( "Since a product of zero means one of the factors must be zero: \n" ); document.write( "y-4=0 or y+1=0 \n" ); document.write( "Adding 4 to both sides of the first equation and subtracting 1 from both sides of the second we get: \n" ); document.write( "y=4 or y=-1 \n" ); document.write( "Now we substitute back in for y: \n" ); document.write( " \n" ); document.write( "We reject the second equation because by definition \n" ); document.write( " \n" ); document.write( "x = 256\r \n" ); document.write( "\n" ); document.write( "Checking: \n" ); document.write( " \n" ); document.write( "16 - 3*4 - 4 = 0 \n" ); document.write( "16 - 12 - 4 = 0 \n" ); document.write( "0 = 0 Check!! \n" ); document.write( " |