document.write( "Question 201467: If Javier has a handful of of coins consisting of dimes,nickles and pennies making a total of 2.63 how much of each coin does he have.. so far what I have is n= nickles p=pennies and d=dimes. The amount of nickles is 1 less than twice of pennies= 2p-1 and the amount of dimes is 3 more the amount of nickles= 2p-1+3d I don't know how to start its..I've tried writing it out like this: .05x(2 (2(.01)x)-1+.10x 2(.01x)-1+3(.10)=2.63 \n" ); document.write( "

Algebra.Com's Answer #151673 by Alan3354(69443) $\"\"$ $\"About$

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If Javier has a handful of of coins consisting of dimes,nickles and pennies making a total of 2.63 how much of each coin does he have?
\n" ); document.write( "The amount of nickles is 1 less than twice of pennies --> n = 2p-1
\n" ); document.write( "The amount of dimes is 3 more the amount of nickels --> d = n + 3
\n" ); document.write( "-----------------
\n" ); document.write( "10d + 5n + p = 263
\n" ); document.write( "n = 2p - 1
\n" ); document.write( "d = n + 3
\n" ); document.write( "-------------
\n" ); document.write( "d = n+3 = 2p+2
\n" ); document.write( "Sub for d and n in the 1st eqn
\n" ); document.write( "10(2p+2) + 5(2p-1) + p = 263
\n" ); document.write( "31p + 15 = 263
\n" ); document.write( "31p = 248
\n" ); document.write( "p = 8
\n" ); document.write( "-----
\n" ); document.write( "n = 15
\n" ); document.write( "------
\n" ); document.write( "d = 18 \n" ); document.write( "

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