document.write( "Question 201421: Please help me solve this problem:
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document.write( "y=1/2x-3
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document.write( "y=1/3x+2\r
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document.write( "I tried this
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document.write( " y=1/3x+2
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document.write( "-1/3x+y=2
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document.write( " -y=-y
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document.write( " -1/3x =-y+2
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document.write( " 3/1(-1/3x)=(-y+2)3/1
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document.write( " x=-3y+6\r
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document.write( "Then substitue x=-3y+6\r
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document.write( " y=1/x(-3y+6)-3
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document.write( " y=-3/xy+6/2-3
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document.write( " y=-3/2y+3-3
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document.write( "But now I am lost \n" );
document.write( "
Algebra.Com's Answer #151643 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! y=1/2x-3 \n" ); document.write( "y=1/3x+2 \n" ); document.write( "------------ \n" ); document.write( "Substitute to get: \n" ); document.write( "(1/2)x - 3 = (1/3)x + 2 \n" ); document.write( "[(1/2)-(1/3)]x = 5 \n" ); document.write( "(1/6)x = 5 \n" ); document.write( "x = 30 \n" ); document.write( "----------- \n" ); document.write( "y = (1/2)30 - 3 \n" ); document.write( "y = 12 \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |