document.write( "Question 201421: Please help me solve this problem:
\n" ); document.write( "y=1/2x-3
\n" ); document.write( "y=1/3x+2\r
\n" ); document.write( "\n" ); document.write( "I tried this
\n" ); document.write( " y=1/3x+2
\n" ); document.write( "-1/3x+y=2
\n" ); document.write( " -y=-y
\n" ); document.write( " -1/3x =-y+2
\n" ); document.write( " 3/1(-1/3x)=(-y+2)3/1
\n" ); document.write( " x=-3y+6\r
\n" ); document.write( "\n" ); document.write( "Then substitue x=-3y+6\r
\n" ); document.write( "\n" ); document.write( " y=1/x(-3y+6)-3
\n" ); document.write( " y=-3/xy+6/2-3
\n" ); document.write( " y=-3/2y+3-3
\n" ); document.write( "
\n" ); document.write( "But now I am lost
\n" ); document.write( "

Algebra.Com's Answer #151643 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
y=1/2x-3
\n" ); document.write( "y=1/3x+2
\n" ); document.write( "------------
\n" ); document.write( "Substitute to get:
\n" ); document.write( "(1/2)x - 3 = (1/3)x + 2
\n" ); document.write( "[(1/2)-(1/3)]x = 5
\n" ); document.write( "(1/6)x = 5
\n" ); document.write( "x = 30
\n" ); document.write( "-----------
\n" ); document.write( "y = (1/2)30 - 3
\n" ); document.write( "y = 12
\n" ); document.write( "======================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );