document.write( "Question 201379: A coin bank contains 25 coins in nickles, dimes and quarters. There are four times as many dimes as quarters. The value of the coins is $2.05. How many dimes are in the bank? \n" ); document.write( "
Algebra.Com's Answer #151640 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
I believe your answer is going to be\r
\n" ); document.write( "\n" ); document.write( "15 nickels (75 cents)
\n" ); document.write( "8 dimes (80 cents)
\n" ); document.write( "2 quarters (50 cents)\r
\n" ); document.write( "\n" ); document.write( "that adds up to be $2.05\r
\n" ); document.write( "\n" ); document.write( "here's how I did it.\r
\n" ); document.write( "\n" ); document.write( "let n = number of nickels
\n" ); document.write( "let d = number of dimes
\n" ); document.write( "let q = number of quarters\r
\n" ); document.write( "\n" ); document.write( "n + d + q = 25 (number of coins in total)\r
\n" ); document.write( "\n" ); document.write( "number of dimes is 4 times the number of quarters (n = 4d)\r
\n" ); document.write( "\n" ); document.write( "total value of coins is $2.05\r
\n" ); document.write( "\n" ); document.write( "$.05 * n + $.10 * d + $.25 * q = $2.05\r
\n" ); document.write( "\n" ); document.write( "take away the dollar sign and multiply both sides of the equation by 100 and you get\r
\n" ); document.write( "\n" ); document.write( "5n + 10d + 25q = 205\r
\n" ); document.write( "\n" ); document.write( "since d = 4q you can substitute to get\r
\n" ); document.write( "\n" ); document.write( "5n + 40q + 25q = 205\r
\n" ); document.write( "\n" ); document.write( "since n + d + q = 25 you can substitute 4q for d again to get\r
\n" ); document.write( "\n" ); document.write( "n + 5q = 25\r
\n" ); document.write( "\n" ); document.write( "solve for n to get\r
\n" ); document.write( "\n" ); document.write( "n = 25 - 5q\r
\n" ); document.write( "\n" ); document.write( "multiply both sides of the equation by 5 to get\r
\n" ); document.write( "\n" ); document.write( "5n = 125 - 25q\r
\n" ); document.write( "\n" ); document.write( "substitute in the equation 5n + 40q + 25q = 205 to get\r
\n" ); document.write( "\n" ); document.write( "125 - 25q + 40q + 25q = 205\r
\n" ); document.write( "\n" ); document.write( "simplify the left side of the equation to get\r
\n" ); document.write( "\n" ); document.write( "125 + 40q = 205\r
\n" ); document.write( "\n" ); document.write( "solve for q to get\r
\n" ); document.write( "\n" ); document.write( "40q = 80\r
\n" ); document.write( "\n" ); document.write( "q = 2\r
\n" ); document.write( "\n" ); document.write( "since d = 4q, then d = 8\r
\n" ); document.write( "\n" ); document.write( "since n + d + q = 25, then n = 15\r
\n" ); document.write( "\n" ); document.write( "your answer is\r
\n" ); document.write( "\n" ); document.write( "n = 15
\n" ); document.write( "d = 8
\n" ); document.write( "q = 2\r
\n" ); document.write( "\n" ); document.write( "as shown above.\r
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