document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=201400>Question 201400</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello! I need a help ASAP!!! <BR>\n" );
document.write( "Problem 3.<BR>\n" );
document.write( "In 1920, the record for a certain race was 46.4 sec. In 1990, it was 45.0 sec.<BR>\n" );
document.write( "Let R(t)= the record in the race and t= the number of the year since 1920.\r<BR>\n" );
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document.write( "a) Find a linear function that the date<BR>\n" );
document.write( "b) Use the function in (a) to predict the record in 2003 and in 2006.<BR>\n" );
document.write( "c) Find the year when the record will be 44.56 sec\r<BR>\n" );
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document.write( "Find a linear function that fits the data.<BR>\n" );
document.write( "R(t)= ?? <BR>\n" );
document.write( "What is the predicted record for 2003? <BR>\n" );
document.write( "What is the predicted record for 2006? <BR>\n" );
document.write( "In what year will the predicted record be 44.56 sec??<BR>\n" );
document.write( "Thank you so much for your help!!!\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #151625 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=151625\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> As  a  linear  relationship, it  follows  the  form,  y=mx +b.<BR>\n" );
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document.write( "In  this  case,,,R=mt +b,,,with  points (0,46.4),,and (70,45)<BR>\n" );
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document.write( "m= (y2-y1) / (x2-x1) = - (46.4 -45) /(1990 - 1920) = -1.4 / 70 = -.02<BR>\n" );
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document.write( "R = (-.02)t +b,,,,,@(0,46.4),,,46.4 = 0 +b,,,b=46.4<BR>\n" );
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document.write( "Base  eqn  ,,,,R = -.02t +46.4<BR>\n" );
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document.write( "@ 1990, t=1990-1920=70,,,R=-.02(70) +46.4 = 45,,,,,good  check<BR>\n" );
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document.write( "@ 2003, t=2003-1920=83,,,R=-.02(83)+46.4 = 44.74<BR>\n" );
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document.write( "@ 2006, t=2006-1920=86,,,R=-.02(86)+46.4 = 44.68<BR>\n" );
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document.write( "Have  a  great  day<BR>\n" );
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