document.write( "Question 201388: Find an equation of the line satisfying the given conditions\r
\n" ); document.write( "\n" ); document.write( "Through (-4,3); perpendicular to -8x+5y=77\r
\n" ); document.write( "\n" ); document.write( "possible answers:
\n" ); document.write( "5x+8y=4
\n" ); document.write( "5x-8y=77
\n" ); document.write( "-8x-5y=4
\n" ); document.write( "5x-8y=4
\n" ); document.write( "

Algebra.Com's Answer #151623 by Alan3354(69443)\"\" \"About 
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Find an equation of the line satisfying the given conditions
\n" ); document.write( "Through (-4,3); perpendicular to -8x+5y=77
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\n" ); document.write( "Find the slope of -8x+5y=77 by putting it in slope-intercept form y=mx+b (that means solve for y).
\n" ); document.write( "-8x+5y=77
\n" ); document.write( "5y = 8x + 77
\n" ); document.write( "y = (8/5)x + 77/5
\n" ); document.write( "The slope, m, is 8/5. Lines perpendicular will have a slope that's the negative invervse, m = -5/8.
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\n" ); document.write( "y-y1 = m*(x-x1) where (x1,y1) is the point (-4,3)
\n" ); document.write( "y-3 = (-5/8)*(x+4)
\n" ); document.write( "8y-24 = -5x - 20
\n" ); document.write( "5x+8y = 4
\n" ); document.write( "
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