document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=201382>Question 201382</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Problem 2.<BR>\n" );
document.write( "In 1920, the record for a certain race was 45.6 sec. In 1990, it was 44.8 sec.<BR>\n" );
document.write( "Let R(t)= the record in the race and t= the number of the year since 1920.<BR>\n" );
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document.write( "a) Find a linear function that the date<BR>\n" );
document.write( "b) Use the function in (a) to predict the record in 2003 and in 2006.<BR>\n" );
document.write( "c) Find the year when the record will be 43.86 sec<BR>\n" );
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document.write( "Find a linear function that fits the data.<BR>\n" );
document.write( "R(t)= ?? -0.02t-45.6???<BR>\n" );
document.write( "What is the predicted record for 2003? <BR>\n" );
document.write( "What is the predicted record for 2006? <BR>\n" );
document.write( "In what year will the predicted record be 43.86 sec??<BR>\n" );
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document.write( "I appreciate this.<BR>\n" );
document.write( "Thank you!  <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #151612 by </B><A HREF=/tutors/aboutme.mpl?userid=user_dude2008><B>user_dude2008(1862)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=user_dude2008><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=151612\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a) \r<BR>\n" );
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document.write( "Function is R(t) = -0.04t + 45.6 (close, but no cigar)\r<BR>\n" );
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document.write( "b) \r<BR>\n" );
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document.write( "2003 ---> t=83\r<BR>\n" );
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document.write( "--> R(83) = -0.04(83) + 45.6 = 42.28\r<BR>\n" );
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document.write( "In 2003, time is approx 42.28 sec.\r<BR>\n" );
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document.write( "2006 ---> t=86\r<BR>\n" );
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document.write( "--> R(86) = -0.04(86) + 45.6 = 42.16\r<BR>\n" );
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document.write( "In 2006, time is approx 42.16 sec.\r<BR>\n" );
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document.write( "c) \r<BR>\n" );
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document.write( "43.86 = -0.04t + 45.6\r<BR>\n" );
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document.write( "43.86 - 45.6 = -0.04t \r<BR>\n" );
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document.write( "-1.74= -0.04t \r<BR>\n" );
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document.write( "t = 43.5\r<BR>\n" );
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document.write( "Year will be 1920+43 = 1963 (mid year) </SPAN>\n" );
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