document.write( "Question 201345: A rectangle is 4 times as long as it is wide. A second rectangle is 5 centimeters longer and 2 centimeters wider than the first. The area of the second rectangle is 270 square centimeters greater than the first. What are the demensions of the original rectangle? \n" ); document.write( "
Algebra.Com's Answer #151601 by nerdybill(7384)\"\" \"About 
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A rectangle is 4 times as long as it is wide. A second rectangle is 5 centimeters longer and 2 centimeters wider than the first. The area of the second rectangle is 270 square centimeters greater than the first. What are the demensions of the original rectangle?
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\n" ); document.write( "Let w = width of original rectangle
\n" ); document.write( "then
\n" ); document.write( "4w = length of original rectangle
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\n" ); document.write( "(w+2)(4w+5) = w(4w) + 270 (if you don't see this, write back)
\n" ); document.write( "4w^2+5w+8w+10 = 4w^2 + 270
\n" ); document.write( "4w^2+13w+10 = 4w^2 + 270
\n" ); document.write( "13w+10 = 270
\n" ); document.write( "13w = 260
\n" ); document.write( "w = 20 cm (width of original rectangle)
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\n" ); document.write( "Length:
\n" ); document.write( "4w = 4(20) = 80 cm (length of original rectangle) \n" ); document.write( "
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