document.write( "Question 201334: Please help. I'm not sure I have this done correctly. \r
\n" ); document.write( "\n" ); document.write( "3/-5-x - x/x-3=0
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Algebra.Com's Answer #151599 by MathTherapy(10552)\"\" \"About 
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\"3%2F%28-5-x%29-x%2F%28x-3%29+=+0\"\r
\n" ); document.write( "\n" ); document.write( "Multiply equation by LCD (-5-x)(x-3). This gives us: \r
\n" ); document.write( "\n" ); document.write( "3(x-3) – x(-5-x) = 0(-5-x)(x-3) = \"3x-9%2B5x%2Bx%5E2+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x-9%2B5x%2Bx%5E2+=+0\" = \"x%5E2+%2B+8x+-+9+=+0\"\r
\n" ); document.write( "\n" ); document.write( "(x + 9)(x – 1) = 0\r
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\n" ); document.write( "\n" ); document.write( "Therefore, x = - 9 or 1, or {- 9, 1}.\r
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\n" ); document.write( "\n" ); document.write( "Checking, when x = - 9\r
\n" ); document.write( "\n" ); document.write( "\"3%2F%28-5-x%29-x%2F%28x-3%29+=+0\" = \"3%2F%28-5-%28-9%29%29--9%2F%28-9-3%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"3%2F%28-5%2B9%29%2B9%2F%28-12%29+=+0\" = \"3%2F4%2B9%2F%28-12%29+=+0\" \r
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\n" ); document.write( "\n" ); document.write( "Multiply equation by LCD, - 12
\n" ); document.write( "-3(3) + 1(9), or, -9 + 9 = 0 (TRUE)\r
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\n" ); document.write( "\n" ); document.write( "Checking, when x = 1\r
\n" ); document.write( "\n" ); document.write( "\"3%2F%28-5-x%29-x%2F%28x-3%29+=+0\" = \"3%2F%28-5-1%29-1%2F%281-3%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"3%2F%28-5-1%29-1%2F%281-3%29+=+0\" = \"3%2F-6-1%2F-2+=+0\" \r
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\n" ); document.write( "\n" ); document.write( "Multiply equation by LCD, - 6
\n" ); document.write( "1(3) – 3(1) = 0, or, 3 – 3 = 0 (TRUE)
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