document.write( "Question 201334: Please help. I'm not sure I have this done correctly. \r
\n" );
document.write( "\n" );
document.write( "3/-5-x - x/x-3=0 \n" );
document.write( "
Algebra.Com's Answer #151599 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "\n" ); document.write( "Multiply equation by LCD (-5-x)(x-3). This gives us: \r \n" ); document.write( "\n" ); document.write( "3(x-3) – x(-5-x) = 0(-5-x)(x-3) = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x + 9)(x – 1) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, x = - 9 or 1, or {- 9, 1}.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Checking, when x = - 9\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply equation by LCD, - 12 \n" ); document.write( "-3(3) + 1(9), or, -9 + 9 = 0 (TRUE)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Checking, when x = 1\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply equation by LCD, - 6 \n" ); document.write( "1(3) – 3(1) = 0, or, 3 – 3 = 0 (TRUE) \n" ); document.write( " \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |