document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=201311>Question 201311</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A father is 8 times as old as his son and 4 times as old as his daughter. If the daughter is 5 years older than the son;how old is each? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #151533 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=151533\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=son's age<BR>\n" );
document.write( "Then x+5=daughter's age<BR>\n" );
document.write( "8x=father's age<BR>\n" );
document.write( "Also 4(x+5)=father's age, so:<BR>\n" );
document.write( "8x=4(x+5) get rid of parens<BR>\n" );
document.write( "8x=4x+20  subtract 4x from each side<BR>\n" );
document.write( "8x-4x=4x-4x+20<BR>\n" );
document.write( "4x=20  divide each side by 4<BR>\n" );
document.write( "x=5--------------son's age<BR>\n" );
document.write( "x+5=5+5=10 daughter's age<BR>\n" );
document.write( "8x=8*5=40-----------father's age\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "8*5=4(5+5)<BR>\n" );
document.write( "40=40\r<BR>\n" );
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document.write( "Hope this helps----ptaylor </SPAN>\n" );
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