document.write( "Question 27818: How so you solve this problem? Photoworks.com charges $7.00 forr processing a 24-exsposure roll and $10.00 for processing a 36-expsosure. After Karens photography field trip, she sent 19 rolls of film to photoworks and pid $151 dollars for processing. How many rolls of each type were processed \n" ); document.write( "
Algebra.Com's Answer #15152 by bmauger(101)\"\" \"About 
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This is a type of problem solved by 2 simultaneous linear equations. You can tell this because you are trying to solve for two unknowns (# of 36-rolls & # of 24-rolls) Let x = the number of 24-exposure rolls that Karen submits, and y equal the number of 36-rolls submitted. From the problem, we are told that the total number of rolls is 19. So the number of 24-rolls (x) and the number of 36-rolls (y) must add up to 19. Or:
\n" ); document.write( "\"x%2By=19\"
\n" ); document.write( "But we can't yet solve this for x or y without knowing something more about them. The other part of the problem says she paid $151 for the total. The amount she'll pay for 24 exposure rolls (x) will be $7/roll or 7x. The amount she'll pay for 36-rolls is $10/roll or 10y. The total she'll pay is the sum of these two amounts, or:
\n" ); document.write( "\"7x%2B10y=151\"
\n" ); document.write( "Now we have to solve these equations. The easiest way is using substitution, so we'll rewrite the first equation for x:
\n" ); document.write( "\"x%2By=19\"subtract y from both sides:
\n" ); document.write( "\"x=19-y\"
\n" ); document.write( "Now we can substitute 19-y for x in the second equation:
\n" ); document.write( "\"7x%2B10y=151\"Substitute:
\n" ); document.write( "\"7%2819-y%29%2B10y=151\"Distibute:
\n" ); document.write( "\"133-7y%2B10y=151\"Rearrange:
\n" ); document.write( "\"3y=18\"Divide:
\n" ); document.write( "\"y=6\"
\n" ); document.write( "So she'll process 6 36-exposure rolls, and 19-6= 13 rolls of 24 exposures.
\n" ); document.write( "\"13%2A7%2B6%2A10=151\"Check.
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