document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=201289>Question 201289</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The ratio of the areas of two squares is 6:1. find the corresponding ratio of the lengths of the diagonals of the two squares ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #151514 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=151514\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let s=length of a side and A=area<BR>\n" );
document.write( "s^2=A<BR>\n" );
document.write( "when s=1 then area=1<BR>\n" );
document.write( "when s=sqrt(6) the area=6<BR>\n" );
document.write( "The length of the diagonals can be found using a^2+b^2=c^2<BR>\n" );
document.write( "1+1=2<BR>\n" );
document.write( "diagonal =sqrt(2)<BR>\n" );
document.write( "6+6=12<BR>\n" );
document.write( "diagonal = sqrt(12)<BR>\n" );
document.write( "=sqrt(4*3)<BR>\n" );
document.write( "=2sqrt(3)<BR>\n" );
document.write( "The ratio of the lengths of the diagonals is 2sqrt(3):sqrt(2)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );