document.write( "Question 201289: The ratio of the areas of two squares is 6:1. find the corresponding ratio of the lengths of the diagonals of the two squares ? \n" ); document.write( "
Algebra.Com's Answer #151513 by josmiceli(19441)\"\" \"About 
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let \"A%5B1%5D\" = the area of the larger square
\n" ); document.write( "Let \"A%5B2%5D\" = the area of the smaller square
\n" ); document.write( "Let \"x\" = the side of the larger square
\n" ); document.write( "Let \"y\" = the side of the smaller square
\n" ); document.write( "given:
\n" ); document.write( "\"A%5B1%5D+%2F+A%5B2%5D+=+6+%2F+1\"
\n" ); document.write( "-------------------------
\n" ); document.write( "\"A%5B1%5D+=+x%5E2\" definition
\n" ); document.write( "\"A%5B2%5D+=+y%5E2\" definition
\n" ); document.write( "Substituting:
\n" ); document.write( "\"x%5E2+%2F+y%5E2+=+6+%2F+1\"
\n" ); document.write( "Take the square roots of both sides
\n" ); document.write( "\"x+%2F+y+=+sqrt%286%29+%2F+1\"
\n" ); document.write( "Also by definition,
\n" ); document.write( "larger diagonal = \"sqrt%282%29%2Ax\"
\n" ); document.write( "Smaller diagonal = \"sqrt%282%29%2Ay\"
\n" ); document.write( "larger diagonal / smaller diagonal = \"%28sqrt%282%29%2Ax%29+%2F+%28sqrt%282%29%2Ay%29\"
\n" ); document.write( "larger diagonal / smaller diagonal = \"x%2Fy\"
\n" ); document.write( "larger diagonal / smaller diagonal = \"sqrt%286%29%2F1\" answer
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