document.write( "Question 201281: R \n" ); document.write( "
Algebra.Com's Answer #151507 by javeria13(7)![]() ![]() ![]() You can put this solution on YOUR website! OKAY.. \n" ); document.write( "all you have to do is make a tree diagram. first on a paper write this down.\r \n" ); document.write( "\n" ); document.write( "A= 1,2,3,4,5,6\r \n" ); document.write( "\n" ); document.write( "B=1,2,3,4,5,6\r \n" ); document.write( "\n" ); document.write( "B=1,2,3,4,5,6\r \n" ); document.write( "\n" ); document.write( "C=1,2,3,4,5,6\r \n" ); document.write( "\n" ); document.write( "C=1,2,3,4,5,6\r \n" ); document.write( "\n" ); document.write( "C=1,2,3,4,5,6\r \n" ); document.write( "\n" ); document.write( "So there are a total of 36 outcomes beacuse there are 36 possible numbers that could occur. Out of those the probability of(B,4) occuring is 2/36 or 1/18 (reduced answer) as shown above because there are 2 B'S and each has one 4 in it. \n" ); document.write( " |