document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=201251>Question 201251</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone please help me figure out the rest of this problem.\r<BR>\n" );
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document.write( "Solve and graph the inequality and graph the solution.<BR>\n" );
document.write( "6x-5/7 < 47/6\r<BR>\n" );
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document.write( "I got 359/36 but which infinity sign goes with it is it a postive infinity or negative infinity </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #151455 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=151455\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "Presuming you meant <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \frac{6x - 5}{7} < \frac{47}{6}\"> instead of <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large 6x - \frac{5}{7} < \frac{47}{6}\"> (and the way you wrote it, it can be interpreted either way), then you have calculated the endpoint correctly.  Note that <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \frac{359}{36} \approx 10\">.\r<BR>\n" );
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document.write( "Pick an integer less than 10, like 9, and substitute it into your original inequality.  If you end up with a true statement, then your number line arrow will go to the left, that is so 9 is included in your solution set.  Otherwise the arrow goes the other way.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
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