document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=201191>Question 201191</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I can't come up with a solution to this can some one help please?<BR>\n" );
document.write( "X+Y+2Z=8<BR>\n" );
document.write( "X+Y+5Z=11<BR>\n" );
document.write( "X+6Y+4Z=30 THE TRIPLE SOLUTION SET IS? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #151426 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=151426\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> subtracting the 1st equation from the 2nd ___ 3Z = 3 ___ so, Z = 1\r<BR>\n" );
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document.write( "substituting gives ___ X + Y = 6<BR>\n" );
document.write( "and ___ X + 6Y = 24\r<BR>\n" );
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document.write( "subtracting the two new equations gives ___ 5Y = 18 ___ so, Y = 3.6 (or 18/5)\r<BR>\n" );
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document.write( "substituting ___ X + 3.6 = 6 ___ X = 2.4 (or 12/5) </SPAN>\n" );
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