document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27794>Question 27794</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tin that was 48% pure was melted together with tin that was 44% pure to make 20 kilograms of an alloy that was 45% pure. How many kilograms of each were used? How do you set it up? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15142 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15142\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.48x+0.44(20-x)=0.45(20)<BR>\n" );
document.write( "0.48+8.8-0.44x=9<BR>\n" );
document.write( "0.04x=0.2<BR>\n" );
document.write( "x=5\r<BR>\n" );
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document.write( "20-5=15\r<BR>\n" );
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document.write( "Hence, for 48% about 5 kg was used and for 44% about 15 kg was used.<BR>\n" );
document.write( "Paul.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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