document.write( "Question 201194: Use the quadratic formula to solve the equation. Give both exact and approximate answers.\r
\n" ); document.write( "\n" ); document.write( "3m2 + 12m + 5 = 0
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Algebra.Com's Answer #151410 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"3m%5E2%2B12m%2B5=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "Notice that the quadratic \"3m%5E2%2B12m%2B5\" is in the form of \"Am%5E2%2BBm%2BC\" where \"A=3\", \"B=12\", and \"C=5\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"m\":\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%28-%2812%29+%2B-+sqrt%28+%2812%29%5E2-4%283%29%285%29+%29%29%2F%282%283%29%29\" Plug in \"A=3\", \"B=12\", and \"C=5\"\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%28-12+%2B-+sqrt%28+144-4%283%29%285%29+%29%29%2F%282%283%29%29\" Square \"12\" to get \"144\". \r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%28-12+%2B-+sqrt%28+144-60+%29%29%2F%282%283%29%29\" Multiply \"4%283%29%285%29\" to get \"60\"\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%28-12+%2B-+sqrt%28+84+%29%29%2F%282%283%29%29\" Subtract \"60\" from \"144\" to get \"84\"\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%28-12+%2B-+sqrt%28+84+%29%29%2F%286%29\" Multiply \"2\" and \"3\" to get \"6\". \r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%28-12+%2B-+2%2Asqrt%2821%29%29%2F%286%29\" Simplify the square root (note: If you need help with simplifying square roots, check out this solver) \r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%28-12%2B2%2Asqrt%2821%29%29%2F%286%29\" or \"m+=+%28-12-2%2Asqrt%2821%29%29%2F%286%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%28-6%2Bsqrt%2821%29%29%2F%283%29\" or \"m+=+%28-6-sqrt%2821%29%29%2F%283%29\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"m+=+%28-6%2Bsqrt%2821%29%29%2F%283%29\" or \"m+=+%28-6-sqrt%2821%29%29%2F%283%29\" \r
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\n" ); document.write( "\n" ); document.write( "which approximate to \"m=-0.472\" or \"m=-3.528\"
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