document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=201145>Question 201145</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers A and B is 3. The sum of their cubes is 36, What is the sum of their squares decreased by the product of the two numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #151388 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=151388\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1) A + B = 3,,,,,,,,B=(3-A)<BR>\n" );
document.write( "(2) A^3 + B^3 =36<BR>\n" );
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document.write( "A^3 + (3-A)^3 =36<BR>\n" );
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document.write( "side  problem (3-A)^3 = (3-A) (3-A)(3-A)<BR>\n" );
document.write( "(3-A) ( 9-6A +A^2)<BR>\n" );
document.write( "27 -27A +9A^2 -A^3<BR>\n" );
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document.write( "subst  in<BR>\n" );
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document.write( "A^3 +(27 -27A +9A^2 -A^3) =36<BR>\n" );
document.write( "9A^2 -27A -9 =0<BR>\n" );
document.write( "9(A^2 -3A -1) =0<BR>\n" );
document.write( "(A^2 -3A -1) =0<BR>\n" );
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document.write( "To  factor  use  quadratic  eqn<BR>\n" );
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document.write( "a=1,,,,,b=-3,,,,,c=-1<BR>\n" );
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document.write( "A =[ -(-3) +/- sqrt((-3)^2 - 4 (1)(-1)] / 2(1)<BR>\n" );
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document.write( "A= [3 +/- sqrt{ 9+4} ]/2<BR>\n" );
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document.write( "A= [3 +/- 3.6]/2<BR>\n" );
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document.write( "A= 3.3, -.3,,,,,<BR>\n" );
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document.write( "B= 3-3.3 =-.3,,,,or  B= 3-(-.3) = 3.3<BR>\n" );
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document.write( "( A^2 +B^2) - AB =?<BR>\n" );
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document.write( "{ (3.3)^2 +(-.3)^2 } - (3.3)(-.3) = ?<BR>\n" );
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document.write( "11+10 = ?<BR>\n" );
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document.write( "21=?\r<BR>\n" );
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document.write( " </SPAN>\n" );
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