document.write( "Question 27759: could i get some help with this please??
\n" ); document.write( "sqrt (75a^2b^3c)
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Algebra.Com's Answer #15136 by sdmmadam@yahoo.com(530)\"\" \"About 
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sqrt (75a^2b^3c)
\n" ); document.write( "sqrt (75a^2b^3c)
\n" ); document.write( "=(75a^2b^3c)^(1/2)
\n" ); document.write( "= [{3X(5^2)}^(1/2)][(a^2)^(1/2)][(b^3)^(1/2)][(c)^(1/2)]
\n" ); document.write( "using (abcd)^m = [(a)^m][(b)^m][(c)^m][(d)^m]
\n" ); document.write( "=[3^(1/2)X5]X(a)X[(b)^(3/2)][c^(1/2)]
\n" ); document.write( "=5a[3^(1/2)][c^(1/2)][(b)^(3/2)]
\n" ); document.write( "Verification: Since our answer is the square root of the given quantity, if we square our answer then it should be the given quantity.
\n" ); document.write( "Therefore {5a[3^(1/2)][c^(1/2)][(b)^(3/2)]} squared
\n" ); document.write( "= 25 X (a^2) X (3) X (c) X (b^3)
\n" ); document.write( "= 75 a^2b^3c
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