document.write( "Question 201093: You drive to houston and back in 8 hours. Suppose your returning speed is 10mph slower than your going speed and that the total trip is 300 miles. What was your speed going to houston? \n" ); document.write( "
Algebra.Com's Answer #151351 by stanbon(75887)\"\" \"About 
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You drive to houston and back in 8 hours. Suppose your returning speed is 10mph slower than your going speed and that the total trip is 300 miles. What was your speed going to houston?
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\n" ); document.write( "Note: Distance to Houston must be 150 miles
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\n" ); document.write( "To-Houston DATA:
\n" ); document.write( "distance = 150 mi ; rate = x mph ; time = 150/x hrs
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\n" ); document.write( "From-Houston DATA:
\n" ); document.write( "distance = 150 mi ; rate = x-10mph ; time = 150/(x-10)
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\n" ); document.write( "Equation:
\n" ); document.write( "time + time = 8 hrs.
\n" ); document.write( "150/x + 150/(x-10) = 8
\n" ); document.write( "150(x-10) + 150x = 8x(x-10)
\n" ); document.write( "300x - 1500 = 8x^2 -80x
\n" ); document.write( "8x^2 -380x + 1500 = 0
\n" ); document.write( "2x^2 - 95x + 375 = 0
\n" ); document.write( "x = [95 +- sqrt(95^2 - 4*2*375)]/4
\n" ); document.write( "x = 43.155 mph (rate to-Houston)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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