document.write( "Question 201093: You drive to houston and back in 8 hours. Suppose your returning speed is 10mph slower than your going speed and that the total trip is 300 miles. What was your speed going to houston? \n" ); document.write( "
Algebra.Com's Answer #151351 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! You drive to houston and back in 8 hours. Suppose your returning speed is 10mph slower than your going speed and that the total trip is 300 miles. What was your speed going to houston? \n" ); document.write( "-------------------------------------- \n" ); document.write( "Note: Distance to Houston must be 150 miles \n" ); document.write( "------------- \n" ); document.write( "To-Houston DATA: \n" ); document.write( "distance = 150 mi ; rate = x mph ; time = 150/x hrs \n" ); document.write( "--------- \n" ); document.write( "From-Houston DATA: \n" ); document.write( "distance = 150 mi ; rate = x-10mph ; time = 150/(x-10) \n" ); document.write( "-------------------- \n" ); document.write( "Equation: \n" ); document.write( "time + time = 8 hrs. \n" ); document.write( "150/x + 150/(x-10) = 8 \n" ); document.write( "150(x-10) + 150x = 8x(x-10) \n" ); document.write( "300x - 1500 = 8x^2 -80x \n" ); document.write( "8x^2 -380x + 1500 = 0 \n" ); document.write( "2x^2 - 95x + 375 = 0 \n" ); document.write( "x = [95 +- sqrt(95^2 - 4*2*375)]/4 \n" ); document.write( "x = 43.155 mph (rate to-Houston) \n" ); document.write( "=================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=================================== \n" ); document.write( " \n" ); document.write( " |