document.write( "Question 201094: The area fo a rectangle is 66ft squared and the diagonal of the rectangle is square root of 157 ft. What are the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #151350 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! The area fo a rectangle is 66ft squared and the diagonal of the rectangle is square root of 157 ft. What are the dimensions of the rectangle. \n" ); document.write( ". \n" ); document.write( "Let x = width \n" ); document.write( "and y = length \n" ); document.write( ".\r \n" ); document.write( "\n" ); document.write( "Since we have two unknowns, we'll need two equations: \n" ); document.write( "Equation 1: \n" ); document.write( "xy = 66 \n" ); document.write( "Equation 2: \n" ); document.write( " \n" ); document.write( "x^2 + y^2 = 157 \n" ); document.write( ". \n" ); document.write( "Solving equation 1 for y: \n" ); document.write( "y = 66/x \n" ); document.write( "Substituting the above into equation 2 we can solve for x: \n" ); document.write( "x^2 + y^2 = 157 \n" ); document.write( "x^2 + (66/x)^2 = 157 \n" ); document.write( "x^2 + 4356/x^2 = 157 \n" ); document.write( "x^4 + 4356 = 157x^2 \n" ); document.write( "x^4 - 157x^2 + 4356 = 0 \n" ); document.write( "Factoring we get: \n" ); document.write( "(x^2-121)(x^2-36) = 0 \n" ); document.write( "x = {11,6} \n" ); document.write( ". \n" ); document.write( "Dimensions of rectangle are 11 feet by 6 feet \n" ); document.write( " |