document.write( "Question 201094: The area fo a rectangle is 66ft squared and the diagonal of the rectangle is square root of 157 ft. What are the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #151350 by nerdybill(7384)\"\" \"About 
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The area fo a rectangle is 66ft squared and the diagonal of the rectangle is square root of 157 ft. What are the dimensions of the rectangle.
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\n" ); document.write( "Let x = width
\n" ); document.write( "and y = length
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\n" ); document.write( "\n" ); document.write( "Since we have two unknowns, we'll need two equations:
\n" ); document.write( "Equation 1:
\n" ); document.write( "xy = 66
\n" ); document.write( "Equation 2:
\n" ); document.write( "\"x%5E2+%2B+y%5E2+=+sqrt%28157%29%5E2\"
\n" ); document.write( "x^2 + y^2 = 157
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\n" ); document.write( "Solving equation 1 for y:
\n" ); document.write( "y = 66/x
\n" ); document.write( "Substituting the above into equation 2 we can solve for x:
\n" ); document.write( "x^2 + y^2 = 157
\n" ); document.write( "x^2 + (66/x)^2 = 157
\n" ); document.write( "x^2 + 4356/x^2 = 157
\n" ); document.write( "x^4 + 4356 = 157x^2
\n" ); document.write( "x^4 - 157x^2 + 4356 = 0
\n" ); document.write( "Factoring we get:
\n" ); document.write( "(x^2-121)(x^2-36) = 0
\n" ); document.write( "x = {11,6}
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\n" ); document.write( "Dimensions of rectangle are 11 feet by 6 feet
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