document.write( "Question 201095: if the radius of a circle is increase by 4 units, its original area is multiplied by 2. Find the original radius. \n" ); document.write( "
Algebra.Com's Answer #151323 by Earlsdon(6294)\"\" \"About 
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Try this:
\n" ); document.write( "Original area is:
\n" ); document.write( "\"A%5B1%5D+=+pi%2Ar%5E2\"
\n" ); document.write( "The area of the new circle is:
\n" ); document.write( "\"A%5B2%5D+=+2%2AA%5B1%5D\" and \"A%5B2%5D+=+pi%2A%28r%2B4%29%5E2\", so...
\n" ); document.write( "\"pi%2A%28r%2B4%29%5E2+=+2%2Api%2Ar%5E2\"
\n" ); document.write( "\"pi%2A%28r%5E2%2B8r%2B16%29+=+2%2Api%2Ar%5E2\" Divide both sides by \"pi\"
\n" ); document.write( "\"r%5E2%2B8r%2B16+=+2%2Ar%5E2\" Subtract \"r%5E2\" from both sides.
\n" ); document.write( "\"8r%2B16+=+r%5E2\" Rewrite as a quadratic equation in standard form:
\n" ); document.write( "\"r%5E2-8r-16=0\" Solve using the quadratic formula: \"r+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\" where: a = 1, b = -8, and c = -16.
\n" ); document.write( "\"r+=+%28-%28-8%29%2B-sqrt%28%28-8%29%5E2-4%281%29%28-16%29%29%29%2F2%281%29\" Simplify:
\n" ); document.write( "\"r+=+%288%2B-sqrt%2864-%28-64%29%29%29%2F2\"
\n" ); document.write( "\"r+=+%288%2B-sqrt%28128%29%29%2F2\"
\n" ); document.write( "\"r+=+4%2B4sqrt%282%29\" or \"r+=+4-4sqrt%282%29\" or approximately...
\n" ); document.write( "\"highlight_green%28r+=+9.65685%29\" or \"cross%28r+=+-1.65685%29\" Discard the negative solution as the radius can only be a positive value!
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