document.write( "Question 201065: Find the values of a and b that result in the given sum.\r
\n" ); document.write( "\n" ); document.write( "[(a+1)x^2 + bx + 2] + [(b-2)x^2 - ax + 5] = x^2 - 4x + 7\r
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Algebra.Com's Answer #151303 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
[(a+1)x^2 + bx + 2] + [(b-2)x^2 - ax + 5] = x^2 - 4x + 7 ... Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "(a+1)x^2 + bx + 2 + (b-2)x^2 - ax + 5 = x^2 - 4x + 7 ... Remove the brackets\r
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\n" ); document.write( "\n" ); document.write( "[(a+1)x^2+ (b-2)x^2] + [ bx - ax] + [2 + 5] = x^2 - 4x + 7 ... Group like terms.\r
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\n" ); document.write( "\n" ); document.write( "(a+1+b-2)x^2 + (b-a)x + 7 = x^2 - 4x + 7 ... Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "(a+b-1)x^2 + (b-a)x + 7 = x^2 - 4x + 7 ... Simplify\r
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\n" ); document.write( "\n" ); document.write( "Now just equate the coefficients to get the two equations:\r
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\n" ); document.write( "\n" ); document.write( "a+b-1=1
\n" ); document.write( "b-a=-4\r
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\n" ); document.write( "\n" ); document.write( "So simply solve this system (which I'll let you do) using any method to get the answers\r
\n" ); document.write( "\n" ); document.write( "a=3, b=-1\r
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\n" ); document.write( "\n" ); document.write( "If you have any questions, email me at jim_thompson5910@hotmail.com.
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