document.write( "Question 201040: Factor completely.\r
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Algebra.Com's Answer #151276 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"x%5E3y%2B4x%5E2y%5E2-21xy%5E3\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"xy%28x%5E2%2B4xy-21y%5E2%29\" Factor out the GCF \"xy\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's focus on the inner expression \"x%5E2%2B4xy-21y%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at \"1x%5E2%2B4xy-21y%5E2\" we can see that the first term is \"1x%5E2\" and the last term is \"-21y%5E2\" where the coefficients are 1 and -21 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 1 and the last coefficient -21 to get -21. Now what two numbers multiply to -21 and add to the middle coefficient 4? Let's list all of the factors of -21:\r
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\n" ); document.write( "\n" ); document.write( "Factors of -21:\r
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\n" ); document.write( "\n" ); document.write( "-1,-3,-7,-21 ...List the negative factors as well. This will allow us to find all possible combinations\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to -21\r
\n" ); document.write( "\n" ); document.write( "(1)*(-21)\r
\n" ); document.write( "\n" ); document.write( "(3)*(-7)\r
\n" ); document.write( "\n" ); document.write( "(-1)*(21)\r
\n" ); document.write( "\n" ); document.write( "(-3)*(7)\r
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\n" ); document.write( "\n" ); document.write( "note: remember, the product of a negative and a positive number is a negative number\r
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\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to 4? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 4\r
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First NumberSecond NumberSum
1-211+(-21)=-20
3-73+(-7)=-4
-121-1+21=20
-37-3+7=4
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\n" ); document.write( "\n" ); document.write( "From this list we can see that -3 and 7 add up to 4 and multiply to -21\r
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\n" ); document.write( "\n" ); document.write( "Now looking at the expression \"x%5E2%2B4xy-21y%5E2\", replace \"4xy\" with \"-3xy%2B7xy\" (notice \"-3xy%2B7xy\" adds up to \"4xy\". So it is equivalent to \"4xy\")\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bhighlight%28-3xy%2B7xy%29-21y%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's factor \"x%5E2-3xy%2B7xy-21y%5E2\" by grouping:\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-3xy%29%2B%287xy-21y%5E2%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x-3y%29%2B7y%28x-3y%29\" Factor out the GCF of \"x\" out of the first group. Factor out the GCF of \"7y\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B7y%29%28x-3y%29\" Since we have a common term of \"x-3y\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E2-3xy%2B7xy-21y%5E2\" factors to \"%28x%2B7y%29%28x-3y%29\"\r
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\n" ); document.write( "\n" ); document.write( "So this also means that \"x%5E2%2B4xy-21y%5E2\" factors to \"%28x%2B7y%29%28x-3y%29\" (since \"x%5E2%2B4xy-21y%5E2\" is equivalent to \"x%5E2-3xy%2B7xy-21y%5E2\")\r
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\n" ); document.write( "\n" ); document.write( "So our expression goes from \"xy%28x%5E2%2B4xy-21y%5E2%29\" and factors further to \"xy%28x%2B7y%29%28x-3y%29\"\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E3y%2B4x%5E2y%5E2-21xy%5E3\" completely factors to \"xy%28x%2B7y%29%28x-3y%29\"\r
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