document.write( "Question 201020: During a recent survey of 2 classes, 1/3 of the students bring their lunch to school, 1/4 buy their lunch, and 1/6 go home. The remaining 18 students don't eat lunch. How many students are in the 2 classes?\r
\n" ); document.write( "\n" ); document.write( "My niece answered 116. Please verify if this correct, so I can double check our work, it has been several since my Algebra days. Thanks, Cindy
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Algebra.Com's Answer #151260 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Right off the bat you can tell that 116 is not correct. 116 is not evenly divisible by either 3 or 6, so you would have a fractional part of a student bringing their lunch and another fractional part of a student going home. Basically, someone's head and shoulders went home and the rest of their body stayed at school and ate the lunch they brought.\r
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\n" ); document.write( "\n" ); document.write( "Let represent the number of students in the two classes. One third of them bring their lunch, , one fourth of them buy, , one-sixth go home, , and 18 don't eat lunch. And the sum of all these pieces is , so:\r
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\n" ); document.write( "\n" ); document.write( "The lowest common denominator of 3, 4, and 6 is 12, so multiply both sides of the equation by 12:\r
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\n" ); document.write( "\n" ); document.write( "Collect terms:\r
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\n" ); document.write( "\n" ); document.write( "Add to both sides:\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by \r
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\n" ); document.write( "\n" ); document.write( "Check the answer: One-third of 72 is 24, one-fourth of 72 is 18, one-sixth of 72 is 12. 24 plus 18 plus 12 plus 18 is 72. Answer checks.\r
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