document.write( "Question 27749: This is a rational inequality problem, I need help with.\r
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document.write( " a/a+2 > 0, any suggestions, please. \n" );
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Algebra.Com's Answer #15126 by longjonsilver(2297) You can put this solution on YOUR website! this has asymptotes, so there is a break in the curve.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Possibly the best approach is to sketch it, so you can see when it is greater than zero.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We need to figure out the asymptotes. Looking at the equation, if a=-2, the denominator would then be zero and hence the equation is infinite, so a=-2 is NOT allowed: it is the vertical asymptote.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "How, for the horizontal one, consider huge values of a, say 1000...we get 1000/1002 which is nearly 1. Pick 100000, we get 100000/100002...even closer to 1, so \"y\"=1 is the horizontal asymptote.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, where does the curve cross the axes?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when y=0, a = 0, so we can then draw in the 2 parts of the curve...i cannot do it here, so you will have to do it.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From that you can see that the curve is >0 when a>0 and also a<-2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon. \n" ); document.write( " \n" ); document.write( " |