document.write( "Question 201009: Ln(x-1)+Ln(x+3)=Ln5\r
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Algebra.Com's Answer #151259 by RAY100(1637)\"\" \"About 
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ln(x-1) + ln (x+3) = ln 5
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\n" ); document.write( "remember lna+lnb =ln(ab)
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\n" ); document.write( "ln{(x-1)(x+3)} = ln5
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\n" ); document.write( "(x-1)(x+3) =5
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\n" ); document.write( "x^2 +2x -3 =5
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\n" ); document.write( "x^2 +2x -8 =0
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\n" ); document.write( "(x+4)(x-2) = 0
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\n" ); document.write( "x = -4, x=2
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\n" ); document.write( "(x=2),,,,ln { (2)-1} +ln{(2) +3} = ln5,,,,ln 1 +ln 5 =ln5,,,,,ok
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\n" ); document.write( "(x=-4),,ln{ (-4)-1} +ln{(-4)+3} =ln5,,ln-5 +ln-1 =ln5,,,ln(-5*-1) =ln5,,,ok
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