document.write( "Question 27769: The sum of two numbers is 12. Three times the product of the number is 105. What are the numbers?\r
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Algebra.Com's Answer #15124 by Earlsdon(6294)\"\" \"About 
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Let the two numbers be a and b.
\n" ); document.write( "You can write two equations from the problem description.\r
\n" ); document.write( "\n" ); document.write( "\"a+%2B+b+=+12\" Solve this one for a and substitute into the second equation. \"a+=+12-b\"
\n" ); document.write( "\"3ab+=+105\"\r
\n" ); document.write( "\n" ); document.write( "\"3%2812-b%29b+=+105\" Simplify and solve for b.
\n" ); document.write( "\"36b+-+3b%5E2+=+105\" Subtract 105 from both sides of the equation.
\n" ); document.write( "\"36b+-+3b%5E2+-+105+=+0\" Multiply through by -1.
\n" ); document.write( "\"3b%5E2+-+36b+%2B+105+=+0\" Factor out a 3.
\n" ); document.write( "\"3%28b%5E2+-+12b+%2B+35%29+=+0\" Apply the zero products principle.
\n" ); document.write( "\"b%5E2+-+12b+%2B+35+=+0\" Factor this quadratic equation.
\n" ); document.write( "\"%28b+-+7%29%28b+-+5%29+=+0\" Apply the zero products principle again.
\n" ); document.write( "\"b+-+7+=+0\" and/or \"b+-+5+=+0\"
\n" ); document.write( "If \"b+-+7+=+0\" then \"b+=+7\"
\n" ); document.write( "If \"b+-+5+=+0\" then \"b+=+5\"\r
\n" ); document.write( "\n" ); document.write( "The two numbers are: 5 and 7
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